Hi, I am developing a building system based on a map grid. I figured to use this grid (only xy axis based) I would only need to use a simple algorithm where I devide the current player position by the grid size.
Lets say I want to get the nearest grid in range of a player, I need to round the player's position till it's devisible by the grid size to get the X Y position from that grid.

Could anyone explain me how to create a function that rounds the player position to the nearest value where it is devisible by a specified value?

Have you tried floatround?

http://wiki.sa-mp.com/wiki/floatround

(2019-04-14, 10:23 PM)Autorojo Wrote: Have you tried floatround?

http://wiki.sa-mp.com/wiki/floatround

Thanks for your reply, although, that's not what I need.
I need a function which rounds a float to an amount till it's devisible by a specified value.

Try this

stock GetGridValue(grid_size, Float:value)
{
new ivalue = floatround(value);
while (ivalue % grid_size != 0) (ivalue < 0) ? (++ivalue):(--ivalue);
return ivalue;
}

Sorry, I'm trying to wrap my head around this whole grid thing, heck, I'm not even sure what I exactly 'need' to have this working.
I drew an image to show what I have in mind.

With the player's position being: -508.0857,-967.1429
I would need a function that rounds x to be divisible by 1.75 (Right?)
And another function that rounds y to be divisible by 1.606.
The outcome of the rounded x & y axis would be the center of the nearest grid, right?

I suggest you use modulo for this.

Modulo operator will return 0 when it matches a value that is dividable with 1.75 (or 1.606);

https://en.wikipedia.org/wiki/Modulo_operation

In pawn it looks like this: https://forum.sa-mp.com/showthread.php?t=485069

grid position = X: floor(position x / grid size x); Y: floor(position y / grid size y)

(2019-04-15, 09:39 AM)BigETI Wrote: grid position = X: floor(position x / grid size x); Y: floor(position y / grid size y)

Had to reread it a few times haha, but this is indeed what I need. Thanks!